*DECK CSICO SUBROUTINE CSICO (A, LDA, N, KPVT, RCOND, Z) C***BEGIN PROLOGUE CSICO C***PURPOSE Factor a complex symmetric matrix by elimination with C symmetric pivoting and estimate the condition number of the C matrix. C***LIBRARY SLATEC (LINPACK) C***CATEGORY D2C1 C***TYPE COMPLEX (SSICO-S, DSICO-D, CHICO-C, CSICO-C) C***KEYWORDS CONDITION NUMBER, LINEAR ALGEBRA, LINPACK, C MATRIX FACTORIZATION, SYMMETRIC C***AUTHOR Moler, C. B., (U. of New Mexico) C***DESCRIPTION C C CSICO factors a complex symmetric matrix by elimination with C symmetric pivoting and estimates the condition of the matrix. C C If RCOND is not needed, CSIFA is slightly faster. C To solve A*X = B , follow CSICO by CSISL. C To compute INVERSE(A)*C , follow CSICO by CSISL. C To compute INVERSE(A) , follow CSICO by CSIDI. C To compute DETERMINANT(A) , follow CSICO by CSIDI. C C On Entry C C A COMPLEX(LDA, N) C the symmetric matrix to be factored. C Only the diagonal and upper triangle are used. C C LDA INTEGER C the leading dimension of the array A . C C N INTEGER C the order of the matrix A . C C On Return C C A a block diagonal matrix and the multipliers which C were used to obtain it. C The factorization can be written A = U*D*TRANS(U) C where U is a product of permutation and unit C upper triangular matrices , TRANS(U) is the C transpose of U , and D is block diagonal C with 1 by 1 and 2 by 2 blocks. C C KVPT INTEGER(N) C an integer vector of pivot indices. C C RCOND REAL C an estimate of the reciprocal condition of A . C For the system A*X = B , relative perturbations C in A and B of size EPSILON may cause C relative perturbations in X of size EPSILON/RCOND . C If RCOND is so small that the logical expression C 1.0 + RCOND .EQ. 1.0 C is true, then A may be singular to working C precision. In particular, RCOND is zero if C exact singularity is detected or the estimate C underflows. C C Z COMPLEX(N) C a work vector whose contents are usually unimportant. C If A is close to a singular matrix, then Z is C an approximate null vector in the sense that C NORM(A*Z) = RCOND*NORM(A)*NORM(Z) . C C***REFERENCES J. J. Dongarra, J. R. Bunch, C. B. Moler, and G. W. C Stewart, LINPACK Users' Guide, SIAM, 1979. C***ROUTINES CALLED CAXPY, CDOTU, CSIFA, CSSCAL, SCASUM C***REVISION HISTORY (YYMMDD) C 780814 DATE WRITTEN C 890531 Changed all specific intrinsics to generic. (WRB) C 890831 Modified array declarations. (WRB) C 891107 Corrected category and modified routine equivalence C list. (WRB) C 891107 REVISION DATE from Version 3.2 C 891214 Prologue converted to Version 4.0 format. (BAB) C 900326 Removed duplicate information from DESCRIPTION section. C (WRB) C 920501 Reformatted the REFERENCES section. (WRB) C***END PROLOGUE CSICO INTEGER LDA,N,KPVT(*) COMPLEX A(LDA,*),Z(*) REAL RCOND C COMPLEX AK,AKM1,BK,BKM1,CDOTU,DENOM,EK,T REAL ANORM,S,SCASUM,YNORM INTEGER I,INFO,J,JM1,K,KP,KPS,KS COMPLEX ZDUM,ZDUM2,CSIGN1 REAL CABS1 CABS1(ZDUM) = ABS(REAL(ZDUM)) + ABS(AIMAG(ZDUM)) CSIGN1(ZDUM,ZDUM2) = CABS1(ZDUM)*(ZDUM2/CABS1(ZDUM2)) C C FIND NORM OF A USING ONLY UPPER HALF C C***FIRST EXECUTABLE STATEMENT CSICO DO 30 J = 1, N Z(J) = CMPLX(SCASUM(J,A(1,J),1),0.0E0) JM1 = J - 1 IF (JM1 .LT. 1) GO TO 20 DO 10 I = 1, JM1 Z(I) = CMPLX(REAL(Z(I))+CABS1(A(I,J)),0.0E0) 10 CONTINUE 20 CONTINUE 30 CONTINUE ANORM = 0.0E0 DO 40 J = 1, N ANORM = MAX(ANORM,REAL(Z(J))) 40 CONTINUE C C FACTOR C CALL CSIFA(A,LDA,N,KPVT,INFO) C C RCOND = 1/(NORM(A)*(ESTIMATE OF NORM(INVERSE(A)))) . C ESTIMATE = NORM(Z)/NORM(Y) WHERE A*Z = Y AND A*Y = E . C THE COMPONENTS OF E ARE CHOSEN TO CAUSE MAXIMUM LOCAL C GROWTH IN THE ELEMENTS OF W WHERE U*D*W = E . C THE VECTORS ARE FREQUENTLY RESCALED TO AVOID OVERFLOW. C C SOLVE U*D*W = E C EK = (1.0E0,0.0E0) DO 50 J = 1, N Z(J) = (0.0E0,0.0E0) 50 CONTINUE K = N 60 IF (K .EQ. 0) GO TO 120 KS = 1 IF (KPVT(K) .LT. 0) KS = 2 KP = ABS(KPVT(K)) KPS = K + 1 - KS IF (KP .EQ. KPS) GO TO 70 T = Z(KPS) Z(KPS) = Z(KP) Z(KP) = T 70 CONTINUE IF (CABS1(Z(K)) .NE. 0.0E0) EK = CSIGN1(EK,Z(K)) Z(K) = Z(K) + EK CALL CAXPY(K-KS,Z(K),A(1,K),1,Z(1),1) IF (KS .EQ. 1) GO TO 80 IF (CABS1(Z(K-1)) .NE. 0.0E0) EK = CSIGN1(EK,Z(K-1)) Z(K-1) = Z(K-1) + EK CALL CAXPY(K-KS,Z(K-1),A(1,K-1),1,Z(1),1) 80 CONTINUE IF (KS .EQ. 2) GO TO 100 IF (CABS1(Z(K)) .LE. CABS1(A(K,K))) GO TO 90 S = CABS1(A(K,K))/CABS1(Z(K)) CALL CSSCAL(N,S,Z,1) EK = CMPLX(S,0.0E0)*EK 90 CONTINUE IF (CABS1(A(K,K)) .NE. 0.0E0) Z(K) = Z(K)/A(K,K) IF (CABS1(A(K,K)) .EQ. 0.0E0) Z(K) = (1.0E0,0.0E0) GO TO 110 100 CONTINUE AK = A(K,K)/A(K-1,K) AKM1 = A(K-1,K-1)/A(K-1,K) BK = Z(K)/A(K-1,K) BKM1 = Z(K-1)/A(K-1,K) DENOM = AK*AKM1 - 1.0E0 Z(K) = (AKM1*BK - BKM1)/DENOM Z(K-1) = (AK*BKM1 - BK)/DENOM 110 CONTINUE K = K - KS GO TO 60 120 CONTINUE S = 1.0E0/SCASUM(N,Z,1) CALL CSSCAL(N,S,Z,1) C C SOLVE TRANS(U)*Y = W C K = 1 130 IF (K .GT. N) GO TO 160 KS = 1 IF (KPVT(K) .LT. 0) KS = 2 IF (K .EQ. 1) GO TO 150 Z(K) = Z(K) + CDOTU(K-1,A(1,K),1,Z(1),1) IF (KS .EQ. 2) 1 Z(K+1) = Z(K+1) + CDOTU(K-1,A(1,K+1),1,Z(1),1) KP = ABS(KPVT(K)) IF (KP .EQ. K) GO TO 140 T = Z(K) Z(K) = Z(KP) Z(KP) = T 140 CONTINUE 150 CONTINUE K = K + KS GO TO 130 160 CONTINUE S = 1.0E0/SCASUM(N,Z,1) CALL CSSCAL(N,S,Z,1) C YNORM = 1.0E0 C C SOLVE U*D*V = Y C K = N 170 IF (K .EQ. 0) GO TO 230 KS = 1 IF (KPVT(K) .LT. 0) KS = 2 IF (K .EQ. KS) GO TO 190 KP = ABS(KPVT(K)) KPS = K + 1 - KS IF (KP .EQ. KPS) GO TO 180 T = Z(KPS) Z(KPS) = Z(KP) Z(KP) = T 180 CONTINUE CALL CAXPY(K-KS,Z(K),A(1,K),1,Z(1),1) IF (KS .EQ. 2) CALL CAXPY(K-KS,Z(K-1),A(1,K-1),1,Z(1),1) 190 CONTINUE IF (KS .EQ. 2) GO TO 210 IF (CABS1(Z(K)) .LE. CABS1(A(K,K))) GO TO 200 S = CABS1(A(K,K))/CABS1(Z(K)) CALL CSSCAL(N,S,Z,1) YNORM = S*YNORM 200 CONTINUE IF (CABS1(A(K,K)) .NE. 0.0E0) Z(K) = Z(K)/A(K,K) IF (CABS1(A(K,K)) .EQ. 0.0E0) Z(K) = (1.0E0,0.0E0) GO TO 220 210 CONTINUE AK = A(K,K)/A(K-1,K) AKM1 = A(K-1,K-1)/A(K-1,K) BK = Z(K)/A(K-1,K) BKM1 = Z(K-1)/A(K-1,K) DENOM = AK*AKM1 - 1.0E0 Z(K) = (AKM1*BK - BKM1)/DENOM Z(K-1) = (AK*BKM1 - BK)/DENOM 220 CONTINUE K = K - KS GO TO 170 230 CONTINUE S = 1.0E0/SCASUM(N,Z,1) CALL CSSCAL(N,S,Z,1) YNORM = S*YNORM C C SOLVE TRANS(U)*Z = V C K = 1 240 IF (K .GT. N) GO TO 270 KS = 1 IF (KPVT(K) .LT. 0) KS = 2 IF (K .EQ. 1) GO TO 260 Z(K) = Z(K) + CDOTU(K-1,A(1,K),1,Z(1),1) IF (KS .EQ. 2) 1 Z(K+1) = Z(K+1) + CDOTU(K-1,A(1,K+1),1,Z(1),1) KP = ABS(KPVT(K)) IF (KP .EQ. K) GO TO 250 T = Z(K) Z(K) = Z(KP) Z(KP) = T 250 CONTINUE 260 CONTINUE K = K + KS GO TO 240 270 CONTINUE C MAKE ZNORM = 1.0 S = 1.0E0/SCASUM(N,Z,1) CALL CSSCAL(N,S,Z,1) YNORM = S*YNORM C IF (ANORM .NE. 0.0E0) RCOND = YNORM/ANORM IF (ANORM .EQ. 0.0E0) RCOND = 0.0E0 RETURN END