*DECK CDCST
      SUBROUTINE CDCST (MAXORD, MINT, ISWFLG, EL, TQ)
C***BEGIN PROLOGUE  CDCST
C***SUBSIDIARY
C***PURPOSE  CDCST sets coefficients used by the core integrator CDSTP.
C***LIBRARY   SLATEC (SDRIVE)
C***TYPE      COMPLEX (SDCST-S, DDCST-D, CDCST-C)
C***AUTHOR  Kahaner, D. K., (NIST)
C             National Institute of Standards and Technology
C             Gaithersburg, MD  20899
C           Sutherland, C. D., (LANL)
C             Mail Stop D466
C             Los Alamos National Laboratory
C             Los Alamos, NM  87545
C***DESCRIPTION
C
C  CDCST is called by CDNTL.  The array EL determines the basic method.
C  The array TQ is involved in adjusting the step size in relation
C  to truncation error.  EL and TQ depend upon MINT, and are calculated
C  for orders 1 to MAXORD(.LE. 12).  For each order NQ, the coefficients
C  EL are calculated from the generating polynomial:
C    L(T) = EL(1,NQ) + EL(2,NQ)*T + ... + EL(NQ+1,NQ)*T**NQ.
C  For the implicit Adams methods, L(T) is given by
C    dL/dT = (1+T)*(2+T)* ... *(NQ-1+T)/K,   L(-1) = 0,
C    where      K = factorial(NQ-1).
C  For the Gear methods,
C    L(T) = (1+T)*(2+T)* ... *(NQ+T)/K,
C    where      K = factorial(NQ)*(1 + 1/2 + ... + 1/NQ).
C  For each order NQ, there are three components of TQ.
C
C***ROUTINES CALLED  (NONE)
C***REVISION HISTORY  (YYMMDD)
C   790601  DATE WRITTEN
C   900329  Initial submission to SLATEC.
C***END PROLOGUE  CDCST
      REAL EL(13,12), FACTRL(12), GAMMA(14), SUM, TQ(3,12)
      INTEGER I, ISWFLG, J, MAXORD, MINT, MXRD
C***FIRST EXECUTABLE STATEMENT  CDCST
      FACTRL(1) = 1.E0
      DO 10 I = 2,MAXORD
 10     FACTRL(I) = I*FACTRL(I-1)
C                                             Compute Adams coefficients
      IF (MINT .EQ. 1) THEN
        GAMMA(1) = 1.E0
        DO 40 I = 1,MAXORD+1
          SUM = 0.E0
          DO 30 J = 1,I
 30         SUM = SUM - GAMMA(J)/(I-J+2)
 40       GAMMA(I+1) = SUM
        EL(1,1) = 1.E0
        EL(2,1) = 1.E0
        EL(2,2) = 1.E0
        EL(3,2) = 1.E0
        DO 60 J = 3,MAXORD
          EL(2,J) = FACTRL(J-1)
          DO 50 I = 3,J
 50         EL(I,J) = (J-1)*EL(I,J-1) + EL(I-1,J-1)
 60       EL(J+1,J) = 1.E0
        DO 80 J = 2,MAXORD
          EL(1,J) = EL(1,J-1) + GAMMA(J)
          EL(2,J) = 1.E0
          DO 80 I = 3,J+1
 80         EL(I,J) = EL(I,J)/((I-1)*FACTRL(J-1))
        DO 100 J = 1,MAXORD
          TQ(1,J) = -1.E0/(FACTRL(J)*GAMMA(J))
          TQ(2,J) = -1.E0/GAMMA(J+1)
 100      TQ(3,J) = -1.E0/GAMMA(J+2)
C                                              Compute Gear coefficients
      ELSE IF (MINT .EQ. 2) THEN
        EL(1,1) = 1.E0
        EL(2,1) = 1.E0
        DO 130 J = 2,MAXORD
          EL(1,J) = FACTRL(J)
          DO 120 I = 2,J
 120        EL(I,J) = J*EL(I,J-1) + EL(I-1,J-1)
 130      EL(J+1,J) = 1.E0
        SUM = 1.E0
        DO 150 J = 2,MAXORD
          SUM = SUM + 1.E0/J
          DO 150 I = 1,J+1
 150        EL(I,J) = EL(I,J)/(FACTRL(J)*SUM)
        DO 170 J = 1,MAXORD
          IF (J .GT. 1) TQ(1,J) = 1.E0/FACTRL(J-1)
          TQ(2,J) = (J+1)/EL(1,J)
 170      TQ(3,J) = (J+2)/EL(1,J)
      END IF
C                          Compute constants used in the stiffness test.
C                          These are the ratio of TQ(2,NQ) for the Gear
C                          methods to those for the Adams methods.
      IF (ISWFLG .EQ. 3) THEN
        MXRD = MIN(MAXORD, 5)
        IF (MINT .EQ. 2) THEN
          GAMMA(1) = 1.E0
          DO 190 I = 1,MXRD
            SUM = 0.E0
            DO 180 J = 1,I
 180          SUM = SUM - GAMMA(J)/(I-J+2)
 190        GAMMA(I+1) = SUM
        END IF
        SUM = 1.E0
        DO 200 I = 2,MXRD
          SUM = SUM + 1.E0/I
 200      EL(1+I,1) = -(I+1)*SUM*GAMMA(I+1)
      END IF
      RETURN
      END